Oudot task

H#9: Promotion of three black pawns to three queens in a single solution. Yet unachieved task.

⧖ Jean Oudot (1926-1974).

See also: 100 Dollar theme; Promotion.

Pfeiffer, Gerhard

Die Schwalbe, 1985

Spec. HM

Example: Oudot task
h#9  (2+15)

1.d1=Q Kg1 2.Qd5 Kh1 3.Qf3 gxf3 4.a1=Q f4 5.Qa2 f5 6.Qe6 fxe6 7.c1=Q e7 8.Qc5 e8=S 9.Qa7 Sc7#

Illegal position: 10 black pawns.

View in Helpmate Analyzer

FEN: kn6/1n6/2pp4/8/p7/4p1p1/ppppp1P1/1r2b2K

External links:

Fiebig, Reinhardt

harmonie, 2005

Spec. HM

Example: Oudot task
h#9  (2+14)

1.e1=Q Ka1 2.Qc3+ Kb1 3.Qb3+ axb3 4.f1=Q bxc4 5.Qf4 c5 6.Qd6 cxd6 7.g1=Q d7 8.Qg6 d8=S 9.Qh7 Sf7#

Illegal position: 9 black pawns.

View in Helpmate Analyzer

FEN: 6nk/6n1/4p3/5p2/2p4p/p2p4/P3ppp1/1Kbr4

External links: